考虑一个硅PN结太阳电池其面积为2cm2．若太阳电池掺杂浓度为Na=1.7×1016cm－3 Nd=5×1019cm－3)且已知τn=10μs

大学 2021-02-04 01:47:45 浓度,室温已帮助人

考虑一个硅PN结太阳电池，其面积为2cm²．若太阳电池掺杂浓度为N_a=1.7×10¹⁶cm^-3，N_d=5×10¹⁹cm^-3)且已知τ_n=10μs，τ_p=0.5μs，D_n=9.3cm²/s，D_p=2.5cm²/s，I_L=95mA．在室温下：

热搜：单层建筑物高度不足2.20m者,( )建筑面积?

答案解析

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=4.1×10-12(A)=4.1×10-9(mA)
I=IL-I0(eV/VT-1)=95+4.1×10-9(1-eV/VT) (1)$由式(1)，I=0，得
Voc=0.62(V)$由
$latex.action?latex=ZV57Vl97bVB9L1Zfe1R9fT1cZnJhY3sxK0lfe0x9L0lfezB9fXsxK1Zfe21QfS9WX3tUfX1cYXBw%0D%0Acm94IFxmcmFjezErSV97TH0vSV97MH19ezErVl97b2N9L1Zfe1R9fT1cZnJhY3sxKzk1LzQuMVx0%0D%0AaW1lcyAxMF57LTl9fXsxKzAuNjIvMC4wMjZ9PTkuOFx0aW1lcyAxMF57OH0%3D$
得Vmp=0.54(V)
代入式(1)得
Imp=90.9(mA)
Pm=Vmp·Imp=49.1(mw)$数值解
I-V曲线表示为
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最大电压满足
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通过MATLAB作图求解上式可知，最大电压为VmP=0.55V，所以
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V-I曲线如图所示．