设总体X服从均匀分布U[0 θ] 样本X1 X2 … Xn来自于总体X 求参数θ的置信度为1-α的置信区间.

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设总体X服从均匀分布U[0,θ],样本X1,X2,…,Xn来自于总体X,求参数θ的置信度为1-α的置信区间.

热搜:关于正态分布总体样本均数抽样分布特点描述不正确的是

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  • 因为参数θ的最大似然估计是2.1781E02.jpg,并且latex.action?latex=XGhhdHtcdGhldGEgfQ%3D%3D的密度函数为latex.action?latex=Zl97bn0oeDtcdGhldGEgKT1cbGVmdFx7XGJlZ2lue2FycmF5fXtjY31cZnJhY3tueF57bi0xfX17%0D%0AXHRoZXRhIF57bn19LCAgICYgMO%2B8nHjvvJxcdGhldGEgLFxcMCwgICAgJiDlhbbku5YuXGVuZHth%0D%0AcnJheX0%3D
       令latex.action?latex=WT1cZnJhY3tcaGF0e1x0aGV0YSB9fXtcdGhldGEgfQ%3D%3D,利用概率知识可以证明y的密度函数为fY(y)=nyn-1,0≤y≤1.若选择参数θ的区间估计形式为(latex.action?latex=Y1xoYXR7XHRoZXRhIH0%3D,latex.action?latex=ZFxoYXR7XHRoZXRhIH0%3D),1≤c<d.
       latex.action?latex=UChjXGhhdHtcdGhldGEgfe%2B8nFx0aGV0YSDvvJxkXGhhdHtcdGhldGEgfSk9UFxsZWZ0KCBcZnJh%0D%0AY3sxfXtkfe%2B8nFxmcmFje1xoYXR7XHRoZXRhIH19e1x0aGV0YSB977ycXGZyYWN7MX17Y30gXHJp%0D%0AZ2h0KT1caW50X3sxL2R9XnsxL2N9bnlee24tMX1keQ%3D%3D
       latex.action?latex=PVxsZWZ0KCBcZnJhY3sxfXtjfSBccmlnaHQpXntufS1cbGVmdCggXGZyYWN7MX17ZH0gXHJpZ2h0%0D%0AKV57bn09MS1cYWxwaGEg
       令latex.action?latex=XGxlZnQoIFxmcmFjezF9e2R9IFxyaWdodClee259PVxmcmFje1xhbHBoYSB9ezJ9,latex.action?latex=MS1cbGVmdCggXGZyYWN7MX17Y30gXHJpZ2h0KV57bn09XGZyYWN7XGFscGhhIH17Mn0%3D,从中解出latex.action?latex=ZD1cbGVmdCggXGZyYWN7XGFscGhhIH17Mn0gXHJpZ2h0KV57LTEvbn0%3D,latex.action?latex=Yz1cbGVmdCggMS1cZnJhY3tcYWxwaGEgfXsyfSBccmlnaHQpXnstMS9ufQ%3D%3D。可否选择参数θ的区间估计形式:(latex.action?latex=XGhhdHtcdGhldGEgfQ%3D%3D-a,latex.action?latex=XGhhdHtcdGhldGEgfQ%3D%3D+b),0≤a<b?
       下面我们简单讨论关于置信度1-α、估计的允许误差δ、总体方差σ2和样本容量n之间的关系.