下面代码的输出结果是 list1 = [(m n) for m in 'AB' for n in 'CD'] print(list1)
已帮助 人
下面代码的输出结果是 list1 = [(m,n) for m in "AB" for n in "CD"] print(list1)
A.[("A", "C"), ("A", "D"), ("B", "C"), ("B", "D")]
B.[‘A’,’B’,’C’,’D’]
C.错误
D.["AC", "AD", "BC", "BD"]
![下面代码的输出结果是 list1 = [(m n) for m in 'AB' for n in 'CD'] print(list1)](/uploads/allimg/6-2892160Q9.jpg)
回答
共1条回复-
C
